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			60 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			C++
		
	
	
	
	
	
			
		
		
	
	
			60 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			C++
		
	
	
	
	
	
| // ArduinoJson - arduinojson.org
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| // Copyright Benoit Blanchon 2014-2019
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| // MIT License
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| //
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| // This example shows how to deserialize a JSON document with ArduinoJson.
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| 
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| #include <iostream>
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| #include "ArduinoJson.h"
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| 
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| int main() {
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|   // Root JSON object
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|   //
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|   // Inside the brackets, 300 is the size of the memory pool in bytes.
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|   // Don't forget to change this value to match your JSON document.
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|   // Use arduinojson.org/assistant to compute the capacity.
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|   StaticJsonDocument<300> doc;
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| 
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|   // StaticJsonDocument<N> allocates memory on the stack, it can be
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|   // replaced by DynamicJsonObject which allocates in the heap.
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|   //
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|   // DynamicJsonObject doc(200);
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| 
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|   // JSON input string.
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|   //
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|   // It's better to use a char[] as shown here.
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|   // If you use a const char* or a String, ArduinoJson will
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|   // have to make a copy of the input in the JsonBuffer.
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|   char json[] =
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|       "{\"sensor\":\"gps\",\"time\":1351824120,\"data\":[48.756080,2.302038]}";
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| 
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|   // Deserialize the JSON document
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|   DeserializationError error = deserializeJson(doc, json);
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| 
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|   // Test if parsing succeeds.
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|   if (error) {
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|     std::cerr << "deserializeJson() failed: " << error.c_str() << std::endl;
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|     return 1;
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|   }
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| 
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|   // Get the root object in the document
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|   JsonObject root = doc.as<JsonObject>();
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| 
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|   // Fetch values.
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|   //
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|   // Most of the time, you can rely on the implicit casts.
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|   // In other case, you can do doc["time"].as<long>();
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|   const char* sensor = root["sensor"];
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|   long time = root["time"];
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|   double latitude = root["data"][0];
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|   double longitude = root["data"][1];
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| 
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|   // Print values.
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|   std::cout << sensor << std::endl;
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|   std::cout << time << std::endl;
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|   std::cout << latitude << std::endl;
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|   std::cout << longitude << std::endl;
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| 
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|   return 0;
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| }
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